Playground

Streamlines in a pipe transition from laminar to turbulent as Reynolds number crosses ~2300. Adjust velocity and viscosity.

Variables

SymbolNameSIDimensionRange
ReReReynolds Numberoutput
Dimensionless flow regime indicator
dimensionless10 – 1000000
ρρDensity
Fluid density
kg/m³M·L⁻³1 – 13600
vvVelocity
Characteristic flow velocity
m/sL·T⁻¹0 – 50
LLCharacteristic Length
Characteristic length scale (e.g., pipe diameter)
mL0.0001 – 10
μμDynamic Viscosity
Fluid dynamic viscosity
Pa·sM·L⁻¹·T⁻¹0.00001 – 10

Deep dive

Derivation
Re comes from non-dimensionalizing the Navier-Stokes equation. The inertial term ρv·∇v scales as ρv²/L, and the viscous term μ∇²v scales as μv/L². Their ratio is (ρv²/L)/(μv/L²) = ρvL/μ ≡ Re. When Re ≫ 1, inertia dominates; when Re ≪ 1, viscosity dominates.
Experimental verification
Reynolds's original 1883 dye-injection experiment in glass pipes showed sharp laminar-to-turbulent transition near Re ≈ 2000. Repeated countless times since with hot-wire anemometry, PIV, and DNS simulations.
Common misconceptions
  • Re = 2300 is NOT a universal turbulence threshold — it's specific to pipe flow
  • Re depends on the chosen characteristic length L — different choices give different numbers for the same flow
  • High Re does NOT mean 'fast' — it means 'inertially dominated', which can occur at any speed if μ is small enough
Real-world applications
  • Pipe and duct design in plumbing and HVAC
  • Aircraft and ship hydrodynamics scaling (wind tunnel models)
  • Microfluidic device design (low-Re regime)
  • Blood flow analysis in arteries
  • Predicting drag coefficients on spheres and cylinders

Worked examples

Water in a 5 cm pipe at 1 m/s

Given:
ρ:
1000
v:
1
L:
0.05
μ:
0.001
Find: Re
Solution

Re = (1000 × 1 × 0.05) / 0.001 = 50000 → fully turbulent

Bacterium swimming in water

Given:
ρ:
1000
v:
0.00003
L:
0.000002
μ:
0.001
Find: Re
Solution

Re = (1000)(3e-5)(2e-6) / 0.001 = 6e-5 → deeply Stokes regime

Scenarios

What if…
  • scenario:
    What if you doubled the pipe diameter at fixed velocity?
    answer:
    Re doubles. Larger pipes are more prone to turbulence at the same speed — which is why big rivers turbulate easily while capillaries stay laminar.
  • scenario:
    What if you replaced water with honey (1000× more viscous)?
    answer:
    Re drops by 1000×. Honey at 1 m/s in a 5 cm pipe has Re ≈ 50 — well below the turbulence threshold, so it flows in smooth layers.
  • scenario:
    What if you scale a model airplane down 100×?
    answer:
    To preserve Re, you must increase v×L by 100. Wind-tunnel testing uses high-speed flow or pressurized gas to match the full-scale Re — otherwise the flow physics differs.
Limiting cases
  • condition:
    Re < 2300 (pipe)
    result:
    Laminar flow
    explanation:
    Smooth, layered streamlines — viscous forces dominate.
  • condition:
    2300 < Re < 4000
    result:
    Transitional
    explanation:
    Intermittent turbulent bursts — unpredictable regime.
  • condition:
    Re > 4000
    result:
    Turbulent flow
    explanation:
    Chaotic eddies, enhanced mixing — inertial forces dominate.
  • condition:
    Re → 0
    result:
    Stokes (creeping) flow
    explanation:
    Viscosity completely dominates — used for microfluidics and bacteria swimming.

Context

Osborne Reynolds · 1883

Reynolds injected dye into pipe flows and observed the transition from laminar streaks to turbulent swirls, identifying the dimensionless number that governs the transition.

Hook

When does smooth flowing water become a chaotic turbulent mess?

Water (ρ=1000 kg/m³, μ=0.001 Pa·s) flows through a 5 cm pipe at 1 m/s. Find Re and determine if the flow is laminar or turbulent.

Dimensions: [ρvL/μ] = (M·L⁻³)(L·T⁻¹)(L) / (M·L⁻¹·T⁻¹) = (M·L⁻¹·T⁻¹)/(M·L⁻¹·T⁻¹) = 1 ✓ (dimensionless)
Validity: Newtonian fluids; transition Re depends strongly on geometry (≈2300 for pipes, ≈5×10⁵ for flat plates).

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