Playground

Exponential decay curve N(t) with adjustable half-life. Shows remaining fraction and marks half-lives on the timeline.

Variables

SymbolNameSIDimensionRange
NNNumber of nucleioutput
Remaining undecayed nuclei at time t
count10 – 1e+24
N0N_0Initial number of nuclei
Population at t = 0
count11 – 1e+24
λλDecay constant
Probability per unit time of decay
1/sT⁻¹1e-12 – 1
ttTime
Elapsed time since t = 0
sT0 – 1000000000000

Deep dive

Derivation
Each nucleus has constant decay probability λ per unit time. For N nuclei, dN/dt = −λN. Separating variables: dN/N = −λ dt → ln N = −λt + C. Applying N(0) = N_0 gives N(t) = N_0 e^{−λt}. Half-life satisfies ½ = e^{−λt₁ᐟ₂} → t₁ᐟ₂ = (ln 2)/λ.
Experimental verification
Rutherford's α-counting experiments confirmed exponential behavior. Modern liquid scintillation counters and HPGe γ-spectroscopy verify the law over dozens of half-lives. Radiocarbon dating (Libby, 1949 Nobel) cross-checks with tree-ring dendrochronology to <50-yr accuracy.
Common misconceptions
  • Half-life is NOT the average lifetime — ⟨τ⟩ = 1/λ = t₁ᐟ₂/ln 2 ≈ 1.44 t₁ᐟ₂.
  • Decay is genuinely random for each nucleus; only the bulk follows the smooth curve.
  • Decay constants are essentially independent of temperature, pressure, and chemistry (electron-capture isotopes show tiny exceptions).
Real-world applications
  • Carbon-14 dating of organic materials up to ~50,000 years.
  • U-Pb and K-Ar dating of rocks (deep time geology).
  • Medical imaging: ⁹⁹ᵐTc (t₁ᐟ₂ = 6 hr) for SPECT, ¹⁸F (110 min) for PET.
  • Radiotherapy dosing and nuclear reactor fuel burn-up calculations.

Worked examples

Carbon-14 dating of a 25% sample

Given:
N/N_0:
0.25
t_half:
5730
Find: age t
Solution

0.25 = (1/2)^(t/5730) → t/5730 = 2 → t = 11460 yr

Activity of 1 g of Co-60 (t₁ᐟ₂ = 5.27 yr)

Given:
m:
0.001
M:
0.06
t_half:
5.27
Find: Activity A = λN
Solution

λ = ln 2 / (5.27×3.156×10⁷) ≈ 4.17×10⁻⁹ s⁻¹; N ≈ 1.0×10²² → A ≈ 4.2×10¹³ Bq

Scenarios

What if…
  • scenario:
    What if you doubled the sample mass?
    answer:
    N_0 doubles, so the activity at every time doubles, but the half-life and shape of the curve are unchanged.
  • scenario:
    What if you cooled radioactive material to 1 K?
    answer:
    Decay rate is essentially unchanged. Nuclear decay depends on nuclear physics, not thermal energy (~meV vs MeV barriers).
  • scenario:
    What if a daughter is also radioactive?
    answer:
    You get the Bateman equations: secular equilibrium when t₁ᐟ₂(parent) ≫ t₁ᐟ₂(daughter), so daughter activity matches parent — basis of radiogenerators (e.g., ⁹⁹Mo → ⁹⁹ᵐTc).
Limiting cases
  • condition:
    t = 0
    result:
    N = N_0
    explanation:
    Initial population — no decays yet.
  • condition:
    t = t₁ᐟ₂
    result:
    N = N_0/2
    explanation:
    Half-life: defines the timescale of the decay process.
  • condition:
    t → ∞
    result:
    N → 0
    explanation:
    All nuclei eventually decay, but never literally zero in finite time (statistical asymptote).
  • condition:
    λt ≪ 1
    result:
    N ≈ N_0(1 − λt)
    explanation:
    Linear decay regime for small times — useful for activity measurements.

Context

Ernest Rutherford and Frederick Soddy · 1902

Rutherford and Soddy showed radioactive substances transmute exponentially, founding nuclear physics.

Hook

How can we date a 5000-year-old artifact from the carbon inside it?

A sample contains 25% of its original Carbon-14. Given t½ = 5730 yr, how old is it?

Dimensions: [λt] dimensionless: T⁻¹ · T = 1 ✓; both sides of N = N_0 e^{−λt} are pure counts.
Validity: Valid for any large ensemble of identical, statistically independent unstable nuclei. Breaks down for small N (Poisson fluctuations dominate) and for daughter chains where Bateman equations are needed.

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