Nuclear & Particlehigh schoolundergraduate
Photoelectric Effect Equation
Also known as: Einstein's Photoelectric Equation
Light comes in packets of energy hf; only packets above the work-function threshold can free an electron — no matter how intense the beam.
Live simulation
warming up the physics…
Photon hits metal; electron ejected only if hf > φ.
Equivalent forms
A linear equation that buried classical wave theory of light and launched quantum mechanics.
Unit systems
Where it holds
Valid for one-photon processes on metal surfaces in vacuum. Multi-photon processes (visible at very high intensities, e.g., lasers) violate the simple linear relation.
Dimensional analysis
K_\max \to [M\cdot L^{2}\cdot T^{-2}]
Both sides are energy.
Discovery
Albert Einstein · 1905
Einstein explained Lenard's photoelectric observations by postulating light quanta (photons) of energy hf. The discovery earned him the 1921 Nobel Prize — not relativity.
Try this
Why won't bright red light eject electrons but dim ultraviolet will?
UV light of wavelength 200 nm hits a sodium surface (work function 2.28 eV). What is the maximum kinetic energy of ejected electrons?
Research status: stable
Real-world applications
- Photomultiplier tubes (PMTs)
- X-ray photoelectron spectroscopy (XPS) for surface analysis
- Solar cells (photovoltaic effect)
- Image sensors (CCDs and CMOS)
Common misconceptions
- K_max does NOT depend on light intensity — only frequency. Intensity affects the number of electrons, not their energy.
- The work function is a property of the material surface, not of individual electrons.
- Multi-photon photoemission (high intensity laser) allows electrons to be ejected below the classical threshold.
Experimental verification
Millikan's 1916 experiments verified the linear K_max vs f relation and measured h to 0.5% accuracy from the slope. Modern photoemission spectroscopy uses this to map band structures in solids.
Derivation
Photon energy is absorbed entirely by a single electron.
Energy conservation: .
The maximum K is reached for the least-bound electron at the surface, giving K_\max = hf - \varphi.
Limiting cases
hf < ⟶ K_\max = 0No emission below threshold — even infinite intensity won't eject electrons.
⟶ K_\max = 0 (threshold)Marginal case — defines threshold frequency .
hf ≫ ⟶ K_\max \approx hfAt very high frequencies, work function becomes negligible.
What if…
What if we doubled the light intensity?
Twice as many electrons emitted, but K_max stays the same.
What if we used a material with ?
Every photon would eject an electron — like an ideal photon detector.
1
UV on sodium
Given ·
- f:
- 1500000000000000
- h:
- 6.62607015e-34
- φ:
- 3.65e-19
Find · K_max
Steps
- Step 1: Photon energy .
- Step 2: Subtract work function: K_\max = 6.21 - 2.28 = 3.93\,\mathrm{eV}.
- Step 3: Convert: .
Result · K_\max = 6.626e-34 \times 1.5e15 - 3.65e-19 = 9.94e-19 - 3.65e-19 = 6.29 \times 10^{-19} J \approx 3.93\,\mathrm{eV}