Playground

Animated Gaussian wave packet spreading over time in free space. Shows |Psi|^2 and real part of Psi.

Variables

SymbolNameSIDimensionRange
PsiPsiWavefunctionoutput
Complex probability amplitude, function of position and time
m^-3/2L^-3/20 – 1
hbarhbarReduced Planck constant
h / (2*pi)
J*sM*L^2*T^-11.054571817e-34 – 1.054571817e-34
HhatH_hatHamiltonian operator
Total energy operator: kinetic + potential
JM*L^2*T^-20 – 1e-15

Deep dive

Derivation
Postulate a wave description Psi(x,t) with de Broglie p = hbar*k and Einstein E = hbar*omega. A plane wave exp(i(kx - omega*t)) satisfies p -> -i*hbar*d/dx and E -> i*hbar*d/dt when acted upon by these derivative operators. Substituting into the classical E = p^2/(2m) + V gives i*hbar*dPsi/dt = [-hbar^2/(2m)*d^2/dx^2 + V] Psi = H*Psi.
Experimental verification
Every quantum experiment ever done — atomic spectra, electron diffraction, tunneling, STM, quantum dots, Bose-Einstein condensates. Accuracy: QED extends it to parts per trillion for the electron g-2.
Common misconceptions
  • Psi is not directly observable — only |Psi|^2 is a probability density
  • The 'i' is essential — the equation is first-order in time but complex, not second-order real
  • It is NOT a classical wave equation — dispersion is quadratic, not linear
Real-world applications
  • Quantum chemistry (DFT, Hartree-Fock)
  • Semiconductor band structure calculations
  • Quantum computing simulations
  • Nuclear reaction modeling

Worked examples

Free particle plane wave

Given:
V:
0
Find: dispersion relation
Solution

omega = hbar*k^2/(2m)

Stationary state separation

Given:
V:
V(x)
Find: time-independent form
Solution

H*psi(x) = E*psi(x)

Scenarios

What if…
  • scenario:
    What if Psi were real?
    answer:
    The equation would force dPsi/dt = 0 — nothing evolves. Complex amplitudes are essential.
  • scenario:
    What if H depended on time?
    answer:
    Non-autonomous evolution — solve with time-ordered exponential U(t) = T*exp(-i*integral(H dt')/hbar).
  • scenario:
    What if we measure Psi?
    answer:
    Collapse postulate: Psi projects onto an eigenstate of the measured observable (in Copenhagen interpretation).
Limiting cases
  • condition:
    V = 0 (free particle)
    result:
    Plane wave solutions exp(i(kx - omega t))
    explanation:
    With dispersion omega = hbar*k^2/(2m) — quadratic, unlike classical waves.
  • condition:
    Stationary state
    result:
    Psi(x,t) = psi(x)*exp(-i*E*t/hbar)
    explanation:
    Time dependence factors out, reducing to the time-independent Schrödinger equation.
  • condition:
    Classical limit (hbar → 0)
    result:
    Recovers Hamilton-Jacobi equation
    explanation:
    WKB approximation connects quantum amplitudes to classical trajectories.

Context

Erwin Schrödinger · 1926

Inspired by de Broglie's matter waves, Schrödinger wrote down the wave equation governing non-relativistic quantum mechanics.

Hook

What is the 'F = ma' of quantum mechanics?

The wavefunction evolves under this PDE. How does it generalize Newton's second law for quantum systems?

Dimensions:
lhs:
[M*L^2*T^-1]*[T^-1]*[L^-3/2] → [M*L^-1/2*T^-2]
rhs:
[M*L^2*T^-2]*[L^-3/2] → [M*L^-1/2*T^-2]
check:
Both sides match (energy density^1/2 per unit volume). ✓
Validity: Non-relativistic quantum mechanics (v << c). For relativistic systems use Dirac or Klein-Gordon equations. Fails for high-energy pair production.

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