Relativityhigh schoolundergraduate

The Twin Paradox

Also known as: Differential aging · Langevin's twins · Clock paradox

Send one twin on a fast round trip and bring her home: she returns younger than the twin who stayed. There's no paradox — the situations aren't symmetric. The traveling twin must turn around, and that acceleration breaks the symmetry, so it is unambiguously she who logs less proper time along her bent path through spacetime.

τtraveler=τEarth1v2c2\tau_{\text{traveler}} = \tau_{\text{Earth}}\sqrt{1 - \frac{v^2}{c^2}}
Live simulation
warming up the physics…

A rocket loops out and back while two clocks tick; the traveler's clock visibly lags the Earth clock by the Lorentz factor.

Equivalent forms

lorentz form
τtraveler=τEarthγ\tau_{\text{traveler}} = \frac{\tau_{\text{Earth}}}{\gamma}
age difference
Δt=τEarth(11v2/c2)\Delta t = \tau_{\text{Earth}}\left(1 - \sqrt{1 - v^2/c^2}\right)
The 'paradox' dissolves the moment you draw the spacetime diagram: the straight worldline between two events is the one with the *most* elapsed time, not the least.