QuantumFeynman path integralgraduate

Path-Integral Formulation

Also known as: Sum over histories · Functional integral

Ask how a particle gets from A to B and quantum mechanics answers: it takes *every* path at once. Each conceivable trajectory contributes an arrow (a complex phase) of equal length but angle set by that path's classical action S divided by ℏ. Add up all the arrows. Wild, jagged paths have wildly varying phases that cancel by destructive interference; only paths near the one that makes S stationary add up in step. That surviving bundle *is* the classical trajectory — so Newton's principle of least action emerges as the place where quantum phases stop cancelling. It reformulates all of quantum mechanics as a single 'sum over histories.'

K(b,a)=∫D[x(t)]  e iℏS[x(t)]K(b,a) = \int \mathcal{D}[x(t)]\; e^{\,\frac{i}{\hbar} S[x(t)]}
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Many candidate paths connect A and B, each drawn with a rotating phasor; paths far from the least-action line cancel while the central bundle reinforces.

Equivalent forms

⟨xb∣e−iH^T/ℏ∣xa⟩=∫Dx eiS/ℏ\langle x_b|e^{-i\hat H T/\hbar}|x_a\rangle = \int \mathcal{D}x\, e^{iS/\hbar}
S[x]=∫tatbL(x,x˙) dtS[x] = \int_{t_a}^{t_b} L(x,\dot x)\,dt
ψ(xb,tb)=∫K(b,a) ψ(xa,ta) dxa\psi(x_b,t_b) = \int K(b,a)\,\psi(x_a,t_a)\,dx_a
Classical mechanics isn't overturned by quantum theory — it's the leftover when ℏ → 0 and only the least-action path survives the interference. One integral contains both worlds.